Question

root 27^x /3y+4=1 and 8^4-x/3-16^y=0

Answer 1

Answer:

(root 27)^X/3^y+4=1

root3^X/3y+4=1

3^1/3X=3^y+4

1/3X=1

3X=1

X=1

3^y+5=3^1/3X

3^y+4=1/3

y+4=1/3

3y+12=1

3y=1-12

3y=11

y=11/3