root 2x 2-3x-2 root 2 find the zeroes and verify the relationship
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√2x²-3x-2√2=0
√2x²-4x+x-2√2=0
√2x(x-2√2)+1(x-2√2)=0
(√2x+1)(x-2√2)=0
√2x+1=0
x= -1/√2
x-2√2=0
x=2√2
∴ x= (-1/√2) ,(2√2)
Hence the zeros of the given quadratic polynomial are (-1/√2) ,(2√2) −
Verification of the relationship between the roots and the coefficients:
Sum of the roots =(-1/√2) +(2√2)
= (- 1 +4)/√2
=3/√2
Product of the roots = (-1/√2) ×(2√2)
= -2
Ans :- x = (-1/√2) ,(2√2)
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