Root. 2x square -5x +root 2=0
Answers
Answer:
csc
( 2 x ) + √ 2 = 0
Explanation:
Subtract
√ 2
from both sides of the equation.
csc
( 2 x ) = − √ 2
Take the inverse cosecant of both sides of the equation to extract
x
from inside the cosecant.
2 x = arccsc ( − √ 2 ) The exact value of arccsc ( − √ 2 ) is − π 4 . 2 x = − π 4 Divideeachterm by
2 and simplify.
Tap for more steps... x = − π 8
The cosecant function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from
2 π , to find a reference angle. Next, add this reference angle to
π to find the solution in the third quadrant.
2 x = 2 π + π 4 + π= 0
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Answer:
csc
( 2 x ) + √ 2 = 0
Explanation:
Subtract
√ 2
from both sides of the equation.
csc
( 2 x ) = − √ 2
Take the inverse cosecant of both sides of the equation to extract
x
from inside the cosecant.
2 x = arccsc ( − √ 2 ) The exact value of arccsc ( − √ 2 ) is − π 4 . 2 x = − π 4 Divideeachterm by
2 and simplify.
Tap for more steps... x = − π 8
The cosecant function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from
2 π , to find a reference angle. Next, add this reference angle to
π to find the solution in the third quadrant.
2 x = 2 π + π 4 + π= 0
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