Question

Root 2x square +7x+5 root 2 .solve for x

Answer 1

root2x^2+7×+5root2

root2x^2+5×+2×+5root2

root2x (root2x+5×)+root2 (root2x+5)

(root2x+root2)(root2x+5)

root2x=-5;root2x=-root2

x=-5/root2;x=-root2/root 2

it is not ;x=-1

possible for

this

.°.X=-1