Question

root 2x²-3x-2 root 2 =0
solve by factorization method...​

Answer 1

Answer:

x^2-\frac{3}{\sqrt{2}}x-2=0

x^2-\frac{3}{\sqrt{2}}x=2

x^2-\frac{3}{\sqrt{2}}x+(\frac{3}{2\sqrt{2}})^2=2+(\frac{3}{2\sqrt{2}})^2

(x-\frac{3}{2\sqrt{2}})^2=2+\frac{9}{4\times2}

(x-\frac{3}{2\sqrt{2}})^2=\frac{16+9}{8}

(x-\frac{3}{2\sqrt{2}})^2=\frac{25}{8}

x-\frac{3}{2\sqrt{2}}=\pm\sqrt{\frac{25}{8}}

x-\frac{3}{2\sqrt{2}}=\pm\frac{5}{2\sqrt{2}}

x-\frac{3}{2\sqrt{2}}=\frac{5}{2\sqrt{2}}\:\:and\:\:x-\frac{3}{2\sqrt{2}}=-\frac{5}{2\sqrt{2}}

x=\frac{5}{2\sqrt{2}}+\frac{3}{2\sqrt{2}}\:\:and\:\:x-\frac{3}{2\sqrt{2}}=-\frac{5}{2\sqrt{2}}+\frac{3}{2\sqrt{2}}

x=\frac{8}{2\sqrt{2}}\:\:and\:\:x=\frac{-2}{2\sqrt{2}}

x=\sqrt{8}\:\:and\:\:x=\frac{-1}{\sqrt{2}}

Therefore, Value of x is 8 and -1/√2.

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Answer 2

Answer:

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