Question

Root 2xsq +7x+5 root 2=0 by quadratic method.​

Answer 1

Answer:

Step-by-step explanation:

Let p ( x )= √2x² + 7x + 5√2 = 0

⇒ √2x² + 2x + 5x + 5√2 = 0

⇒ √2x ( x + √2 ) + 5 ( x + √2 ) = 0

⇒ ( x + √2 ) ( √2x + 5 ) = 0

⇒ x = - √2 or - 5/√2.