Math, asked by Tkgmailcom8501, 1 year ago

Root 2xsquare - 3x - 2 root 2 is equal to zero

Answers

Answered by Anonymous
3
Hey!!!...here is ur answer

 \sqrt{2}  {x}^{2}  - 3x - 2 \sqrt{2} = 0 \\  \\  \sqrt{2}  {x}^{2}  - 4x + x - 2 \sqrt{2}  = 0 \\  \\  \sqrt{2} x(x - 2 \sqrt{2} ) + 1(x - 2 \sqrt{2} ) = 0 \\  \\ (x - 2 \sqrt{2} )( \sqrt{2} x + 1) = 0 \\  \\ x = 2 \sqrt{2}  \:  \: and \:  \: x =  \frac{ - 1}{ \sqrt{2} }  \\  \\
Hope it will help you
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