Question

root 3 _ 1 / root 3 + 1 rationalize the denominator ​

Answer 1

Step-by-step explanation:

$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } = \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3 } - 1}{\sqrt{3} + 1 }$

$= \frac{ {( \sqrt{3} - 1) }^{2} }{ { (\sqrt{3)} }^{2} - {1}^{2} }$

$= \frac{3 + 1 - 2 \sqrt{3} }{3 - 1}$

$= \frac{4 - 2 \sqrt{3} }{2}$

$= 2 - \sqrt{3}$