Question

root 3 + 1 upon 2 root 2 minus root 3​

Answer 1

Answer:

1/2√2

Step-by-step explanation:

√3 + 1/2√2 - √3

√3 gets cancelled

so it is 1/2√2

Answer 2

$\sqrt{3 + } \binom{1}{2 \sqrt{2} - \sqrt{3} }$

$\frac{2 \sqrt{6} - 3 +1 }{2 \sqrt{2} - \sqrt{3}}$

$\frac{2 \sqrt{6} - 2 }{2 \sqrt{2} - \sqrt{3} }$

$\frac{2 \sqrt{6} - 2}{2 \sqrt{2} - \sqrt{3} } \times \frac{2 \sqrt{2} + \sqrt{3} }{2 \sqrt{2} + \sqrt{3} }$

$\frac{2 \sqrt{12} + 2 \sqrt{18} - 4 \sqrt{2} - 2 \sqrt{3} }{ {2 \sqrt{2} }^{2} - { \sqrt{3} }^{2} }$

$\frac{4 \sqrt{3} + 6 \sqrt{2} - 4 \sqrt{2} - 2 \sqrt{3} }{8 - 3}$

$\frac{2 \sqrt{3} + 2 \sqrt{2} }{5} is \: the \: answer... | . < - .|$

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