Math, asked by saikrishna2325, 11 months ago

root 3^5*9^2=3^n3root3=27 what is the value of n​

Answers

Answered by pattanaik
1

Answer:

Step-by-step explanation:

3×27−−√=3×9×3−−−−√=3×3×3–√=32.5

32.5=3n

log332.5=log33n

2.5=n


saikrishna2325: this is wrong answer
Answered by Srusti18
2

 {3}^{5}  \times  {9}^{2}  =  {3}^{n} \times 3 \sqrt{3 }   \\  =  >  {3}^{5}  \times  {3}^{2 \times 2}  =  {3}^{1 +  \frac{1}{2} }  \times  {3}^{n}  \\  =  >  {3}^{5 + 4}  \div  {3}^{ \frac{3}{2} }  =  {3}^{n}  \\  =  >  {3}^{9 -  \frac{3}{2} }  =  {3}^{n}  \\  =  >  {3}^{ \frac{15}{2} }  =  {3}^{n}  \\  =  > n =  \frac{15}{2}  \\  =  > n = 7.5
Heya mate , hope you are helped...
Regards !!!
Similar questions