Question

root 3 + root 2 divided by
root 5+ root 2
rationalize the denominators
how to solve please help tomorrow my exams
i will mark u brilliant ​

Answer 1

Answer:

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{5} + \sqrt{2} } \\ \\ = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{5} + \sqrt{2} } \times \frac{ \sqrt{5} - \sqrt{2} }{ \sqrt{5 } - \sqrt{2} } \\ \\ = \frac{( \sqrt{3} + \sqrt{2})( \sqrt{5} - \sqrt{2}) }{ {( \sqrt{5}) }^{2} - {( \sqrt{2} )}^{2} } \\ \\ = \frac{ \sqrt{15} - \sqrt{6} + \sqrt{10} - \sqrt{4} }{5 - 2} \\ \\ = \frac{ \sqrt{15} - \sqrt{6} + \sqrt{10} - 2 }{3}$

hope this much helps uh ❣️