Question

root 3 + root 2 upon root 3 minus root 2 rationalize ​

Answer 1

Answer:

$\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}$

= (root 3 + root 2)*(root 3 + root 2)/ (root 3 - root 2 )*(root 3 + root 2)  

= (root 3 + root 2)^2 / 3 - 2

= 3 + 2 + 2$\sqrt{6}$ / 1

= 3 + 2 + 2$\sqrt{6}$