Question

root 3/root 5^x+1=125/27,find x

Answer 1

Root3/root5^x+1=5/3^3
=>Only x=-7 is possible

Answer 2

Answer: x = 7

Step-by-step explanation:

Root 3/root5 can be written as 3/5^1/2

Therefore ,

3/5^1/2×x+1 = 5/3^3

(125 =5^3)(27 =3^3)

Now to get equal base,we can write

3/5^1/2×x+1 = 3/5^ negative 3

Now based are equal

1/2×x+1 =negative 3

By solving those get x =7