Question

(root 3+root 7)whole square ​

Answer 1

Answer:

$52 + 2 \sqrt{21}$

Step-by-step explanation:

${( \sqrt{3} + \sqrt{7} )}^{2}$

$= {( \sqrt{3} )}^{2} + 2 \times \sqrt{3} \times \sqrt{7} + {( \sqrt{7}) }^{2}$

$= 3 + 2 \sqrt{21} + 49$

$= 52 + 2 \sqrt{21} (ans)$

Answer 2

Answer:

(√3+√7)²

using algebraic identity :-

(a+b)²

= a²+2ab+b²

here,

a= √3 and b = √7

so,

(√3)²+2(√3)(√7) + (√7)²

3+2(√21)+7

10+2(√21) is the correct answer.

Step-by-step explanation:

hence, the answer is 10+2√21.