Math, asked by AbhinayPande, 7 months ago

(root 3+root10)square​

Answers

Answered by singhkhushmeet309
0

Answer:

( \sqrt{3}  +  \sqrt{10} ) {}^{2}  \\ ( \sqrt{3} ) {}^{2}  + ( \sqrt{10} ) {}^{2}  + 2( \sqrt{3} )( \sqrt{10} ) \\ 3 + 10 + 2 \sqrt{30}  \\ 13 + 2 \sqrt{30}

Answered by bitterexistence8
0

Answer:

(\sqrt{3} +\sqrt{10} )^{2} \\\

Apply (a+b)^2 = a^2 + 2ab + b^2

So by solving further you get,

13 + 2\sqrt{30}

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