root 3 sin theta =cos thetafind value of sintheta tantheta (1+cottheta)÷sin theta +cos theta please tell the answer
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Answer:
√3
Step-by-step explanation:
√3sinϑ = cosϑ
cosϑ/sinϑ = √3
tanϑ = √3
ϑ = 60°
sinϑ.tanϑ.(1+cotϑ) / sinϑ+cosϑ = sin60.tan60.(1+cot60) / sin60+cos60
= (√3/2) × √3 × (1 + 1/√3) ÷ √3/2 + 1/2
= 3/2 × (√3+1)/√3 ÷ (√3+1)/2
= [3(√3+1)] / 2√3 × 2/(√3+1)
= 3/√3
= 3/√3 × √3/√3
= 3√3/3
= √3
Hope it helps you:)
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