Question

root 3^(x-3) = 4 root 3^(x+ 1) find x​

Answer 1

Answer:

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The value of X = 7

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${( \sqrt{3} )}^{x - 3} = { (\sqrt[4]{3} )}^{x + 1} \\ \\ {(3)}^{ \frac{x - 3}{2} } = {(3)}^{ \frac{x + 1}{4} } \\ \\ \frac{x - 3}{2} = \frac{x + 1}{4} \: \: \: \: \: (because \: {a}^{m} = {a}^{n} \: \: \: then \: = = > m = n) \\ \\ cross \: multiply \\ \\ 4(x - 3) = 2(x + 1) \\ \\ 4x - 12 = 2x + 2 \\ \\ 4x - 2x = 2 + 12 \\ \\ 2x = 14 \\ \\ x = \frac{14}{2} \\ \\ x = 7 \\ \\ this \: is \: ur \: required \: answer \: :):):):):)$