Math, asked by subham6460, 1 year ago

root 3 X + root 2 Y =0 and root 5 x + root 7y =0 .solve the equation by substitution method​

Answers

Answered by daksh4871
6

√3x + √2y = 0 _ _ _ (1)

√5x + √7y = 0 _ _ _ (2)

In (1)→ y = -- √3x\√2

Put in eq. (2)

√5x + √7[-- √3x\√2 ] =0

√5x + [ -- √21x\√2 ] = 0

√5x -- √21x = 0*√2 => 0

-- √16x = 0

x=0

so , y=0 (on putting x=0 in eq. 1or 2)

Answered by divyans91
0

Step-by-step explanation:

root 3 X + root 2 Y =0 and root 5 x + root 7y =0 .solve the equation by substitution method

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