root 3 X + root 2 Y =0 and root 5 x + root 7y =0 .solve the equation by substitution method
Answers
Answered by
6
√3x + √2y = 0 _ _ _ (1)
√5x + √7y = 0 _ _ _ (2)
In (1)→ y = -- √3x\√2
Put in eq. (2)
√5x + √7[-- √3x\√2 ] =0
√5x + [ -- √21x\√2 ] = 0
√5x -- √21x = 0*√2 => 0
-- √16x = 0
x=0
so , y=0 (on putting x=0 in eq. 1or 2)
Answered by
0
Step-by-step explanation:
root 3 X + root 2 Y =0 and root 5 x + root 7y =0 .solve the equation by substitution method
Attachments:
Similar questions