Math, asked by Gaurav11275, 1 year ago

root 3 x - root 2 Y = root 3 ,root 5 x + root 3 Y = root 2 solve by elimination method

Answers

Answered by mysticd
74
Hi ,

√3x - √2y = √3 ---( 1 )

√5x + √3y = √2 ---( 2 )

multiply equation ( 1 ) with √3 and equation

( 2 ) with √2 , we get ,

3x - √6y = 3 --( 3 )

√10x + √6y = 2 --( 4 )

add ( 3 ) and ( 4 ) , we get

3x + √10 x = 5

x ( 3 + √ 10 ) = 5

x = 5/( 3 + √10 )

x = [ 5( √10 - 3 ) ]/( √10 + 3 )( √10 - 3 )]

x = 5( √10 - 3 )/ [ ( √10 )² - ( 3 )² ]

x = 5( √10 - 3 )/ ( 10 - 9 )

x = 5√10 - 15

put x value in equation ( 2 ) , we get ,

√5 ( 5√10 - 15 ) + √3y = √2

25√2 - 15√5 + √3y = √2

√3y = √2 - 25√2 + 15√5

y = ( 15√5 - 24√2 )/√3

y = [ 3( 5√5 - 8√2 ) ]/( √3 )

y = [ √3 × √3 ( 5√5 - 8√2 )]/( √3 )

y = [ √3 ( 5√5 - 8√2 ) ]

y = 5√15 - 8√6

I hope this helps you.

: )


kushaldesai1: best answer
Answered by bngupta52
8

Step-by-step explanation:

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