Question

root 3 X square + 10 X + 7 root 3​

Answer 1

Solution:

Given quadratic expression √3x²+10x+7√3

Splitting the middle term, we get

= √3x² +7x+3x+7√3

= x(√3x+7)+√3(√3x+7)

=(√3x+7)(x+√3)

Therefore,

√3x²+10x+7√3 = (√3x+7)(x+√3)

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Answer 2

$\sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} \\ \\ = \sqrt{3} {x}^{2} + 3x + 7x + 7 \sqrt{3} \\ \\ = \sqrt{3}x ( x + \sqrt{3} ) + 7(x + \sqrt{3} ) \\ \\ =( \sqrt{3} x + 7)(x + \sqrt{3} ) \\ \\ required \: zeroes \: of \: above \\ polynomial \: are \\ \sqrt{3} x + 7 = 0 \\ = > \sqrt{3} x = - 7 \\ = > x = \frac{ - 7}{ \sqrt{3} } \\ \\ and \\ x + \sqrt{3} = 0 \\ = > x = - \sqrt{3}$