Math, asked by mandeep4638, 2 months ago

Root 3 x square +10x+7root 3

Answers

Answered by Anonymous
1

Consider the given quadratic equation.

 \sqrt{3} x^2+10x+7 \sqrt{3}  = 0

 {x}^{2}  +  \frac{10}{ \sqrt{3} } x + 7 = 0

 \small{ {x}^{2}  + 2 \times  \frac{5}{ \sqrt{3}  }  \times x + ( \frac{5}{ \sqrt{3} }){}^{2}  -  \frac{25}{3}  + 7 = 0}

 {(x +  \frac{5}{ \sqrt{3} }) }^{2}  =  \frac{4}{3}

x +  \frac{5}{ \sqrt{3} }  =  \underline{ + } \frac{2}{ \sqrt{3} }

x =  -  \sqrt{3} , -  \frac{7}{ \sqrt{3} }

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