Question

root 3 x square minus 2 root 3 x minus 2 root 3 is equal to zero solve by middle term splitting​

Answer 1

Answer:

Step-by-step explanation:

√3 x^2 - 2√3 x - 2√3 =0

=> √3(x^2 -2x -2)=0

=> x^2 - 2x - 2=0

=> x^2 - [(1 - √3) + (1 + √3)]x - [(√3)^2 - 1^2] = 0

=> x^2 -(1 - √3)x -(1 + √3)x - (√3 - 1)(√3 + 1) = 0

=> x(x - 1 +√3) - (√3 + 1)(x -1 + √3) = 0

=>(x - 1 + √3)(x - √3 -1) = 0

=> x - 1 + √3 = 0         ,     x - √3 - 1 = 1

=> x = 1 - √3               ,     x =  1 + √3

Therefore, the required values of x are (1 - √3) and (1+√3)

HOPE IT HELPS

I don't think most people can solve this by middle term splitting so i think i can  feel proud of myself for a while.