Question

root 3 xsquare +10x -8root 3 =0 solve by quadratic formula

Answer 1

quadratic equation =[-b±√D]/(2a)
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D = discriminant =b²-4ac

____________

Here,

a = √3
b = 10
c = -8√3

Discriminant = b²-4ac

=> (10)² - 4(√3)(-8√3)

=> 100 - 4(-24)

=> 100 + 96

=> 196

Then,

$quadratic \: equation \: = \: \frac{ - b( + and - ) \sqrt{d} }{2a} \\ \\ here \\ \\ roots = \frac{ - 10( + and - ) \sqrt{196} }{2( \sqrt{3} )} \\ \\ = > \frac{ - 10( + and - )14 }{2 \sqrt{3} } \\ \\ taking \: + \\ \\ x \: = \frac{ - 10 + 14}{2 \sqrt{3} } = \frac{4}{2 \sqrt{3} } = \frac{2}{ \sqrt{3} } = \frac{2 \sqrt{3} }{3} \\ \\ taking \: - \\ \\ x = \frac{ - 10 - 14}{2 \sqrt{3} } = \frac{ - 24}{2 \sqrt{3} } = \frac{ - 12}{ \sqrt{3} } = \frac{ - 12 \sqrt{3} }{3} = - 4 \sqrt{3}$



Then,

x = (2√3)/3


Or

x = -4√3

Answer 2

hyy,here is your answer

mark as brainlist