Question

root 32 + root 48 divided by root 8 + root 12 find the value

Answer 1

=(√32+√48)÷(√8+√12)
=(4√2+4√3)÷(2√2+2√3)
=4(√2+√3)÷2(√2+√3)
=4÷2
=2 ans

Answer 2

The value of $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is 2.

$\sqrt{32}$ can be simplified as $\sqrt{16 \times 2}=4 \sqrt{2}$

Similarly,  

$\sqrt{48}$ can be simplified as $\sqrt{16 \times 3}=4 \sqrt{3}$

The same way,

$\sqrt{8}$ can be simplified as $\sqrt{4 \times 2}=2 \sqrt{2}$

$\sqrt{12}$ can be simplified as $\sqrt{3 \times 4}=2 \sqrt{3}$

As per given problem, $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ can be represented by using its simplified form,

Therefore,  

$\begin{array}{l}{=\frac{(4 \sqrt{2}+4 \sqrt{3})}{(2 \sqrt{2})+2 \sqrt{3}}} \\ \\ {=\frac{(4 \sqrt{2}+\sqrt{3})}{(2 \sqrt{2})+\sqrt{3}}} \\ \\ {=2}\end{array}$

∴ The value is found to be 2.