Math, asked by sanasakir93, 1 year ago

root 32 + root 48 divided by root 8 + root 12 find the value

Answers

Answered by cs18thehrtbrkk
3
 \frac{ \sqrt{32}+ \sqrt{48}  }{ \sqrt{8}+ \sqrt{12}  }
= \frac{4 \sqrt{2}+4 \sqrt{3}  }{2 \sqrt{2} +2 \sqrt{3} }
= \frac{4( \sqrt{2} + \sqrt{3}) }{2( \sqrt{2}+ \sqrt{3})  }
= \frac{4}{2}
=2
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