Question

Root 3x-2 = 2root3+4

Answer 1

Answer:

heya mate!!!

here is your answer!!!!!

Ist approach:-

√3x²+2√2x-2√3=0,

√3x²+(3√2-√2)x-2√3=0,

√3x²+3√2x-√2x-2√3=0,

√3x(x+√6)-√2(x+√6)=0,

(x+√6)(√3x-√2)=0,

IInd approach:-

√3x²+2√2x-2√3=0,

divide by √3 in both the sides, we have

x²+2√2x/√3 - 2=0,

x²+2√2x/√3 =2,

x²+2×x×√2/√3 + (√2/√3)²=2+(√2/√3)²,

(x+√2/√3)²=2+2/3

(x+√2/√3)²=8/3

then

(x+√2/√3)=±(2√2/√3),

(x+√2/√3)=±(2√2/3),

taking +ve sign, we have

x+√2/√3 = 2√2/√3,

then

x=2√2/√3 - √2/√3,

then

x=√2/√3,

(√3x-√2)=0,

now taking -ve sign, we have

(x+√2/√3) = -2√2/√3,

then

x=-2√2/√3 - √2/√3,

x=-3√2/√3,

x=-√3/√2,

√2x+√3=0,

You can also solve it with the help of quadratic formula