Question

Root 3x+ 2root 2x- 2 root 3x

Answer 1

Answer:

your question is not corrected

Answer 2

The solution of the equation is $x=\sqrt{6},-\frac{\sqrt{2}}{\sqrt{3}}$.

Step-by-step explanation:

Given : Expression $\sqrt{3}x^2+2\sqrt{2}x-2\sqrt3 =0$

To find : Solve for x ?

Solution :

Solving the quadratic equation by middle term split,

$\sqrt{3}x^2+2\sqrt{2}x-2\sqrt3 =0$

$\sqrt{3}x^2-3\sqrt{2}x+\sqrt{2}x-2\sqrt3 =0$

$\sqrt{3}x(x-\sqrt{6})+\sqrt{2}(x-\sqrt{6}) =0$

$(x-\sqrt{6})(\sqrt{3}x+\sqrt{2}) =0$

$(x-\sqrt{6})=0,(\sqrt{3}x+\sqrt{2}) =0$

$x=\sqrt{6},x=-\frac{\sqrt{2}}{\sqrt{3}}$

Therefore, the solution of the equation is $x=\sqrt{6},-\frac{\sqrt{2}}{\sqrt{3}}$.

#Learn more

Solve this a solve ( X+3) (X-3)

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