Root 3x square - 2root2x - 2root3 =0 solve by quadratic equation formula
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Heya !!!
✓3X² - 2✓2X - 2✓3 = 0
A = Coefficient to X² = ✓3
B = Coefficient to X = -2✓2
And,
C = Constant term = -2✓3
Discriminant ( D ) = B² - 4AC
=> ( -2✓2 )² - 4 × ✓3 × -2✓3
=> 8 + 24
=> 32
=> ✓D = ✓32 = ✓2 × 2 × 2 × 2 × 2 = 4✓2
Therefore,
Root's of the given polynomial = -B + ✓D / 2A and -B - ✓D/2A
=> - ( -2✓2 ) + 4✓2 / 2 × ✓3 OR -(-2✓2) - 4✓2/2✓3
=> 2✓2 + 4✓2 / 2✓3 or 2✓2 - 4✓2/2✓3
=> 6✓2/2✓3 or -2✓2/2✓3
★ HOPE IT WILL HELP YOU ★
✓3X² - 2✓2X - 2✓3 = 0
A = Coefficient to X² = ✓3
B = Coefficient to X = -2✓2
And,
C = Constant term = -2✓3
Discriminant ( D ) = B² - 4AC
=> ( -2✓2 )² - 4 × ✓3 × -2✓3
=> 8 + 24
=> 32
=> ✓D = ✓32 = ✓2 × 2 × 2 × 2 × 2 = 4✓2
Therefore,
Root's of the given polynomial = -B + ✓D / 2A and -B - ✓D/2A
=> - ( -2✓2 ) + 4✓2 / 2 × ✓3 OR -(-2✓2) - 4✓2/2✓3
=> 2✓2 + 4✓2 / 2✓3 or 2✓2 - 4✓2/2✓3
=> 6✓2/2✓3 or -2✓2/2✓3
★ HOPE IT WILL HELP YOU ★
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