Question

root 3x square -8x +4 root 3 ke sunyank gyat kare. ​

Answer 1

Answer:

x=2√3 or 2\√3

Step-by-step explanation:

√3x^2-8x + 4√3=0

for the simple step 4√3×√3=12

in which 8 is the centre number

We may divide 12 as 6×2

therefore √3x^2 - 6X -2x +4√3=0

taking common

√3X(x-2√3) -2(x-2√3)=0

equationg to zero weget

x=2√3 or 2/√3