Question

root 3xsquare - 2 root2x-2root3=0​

Answer 1

Answer:

$(\sqrt{3} ) ^{2} - 2 \sqrt{2} x - 2 \sqrt{3 } = 0$

Step-by-step explanation:

$3 - 2 \sqrt{2}x - 2 \sqrt{3 } = 0$

we can write it as,

$- 2 \sqrt{2} x = 2 \sqrt{3} - 3$

$2 \sqrt{2} x= - (2 \sqrt{3} - 3)$

$x = - (2 \sqrt{3} - 3) \div 2 \sqrt{2}$

$x = (- 2 \sqrt{3 } + 3 ) \div 2 \sqrt{2}$

By rationalising..

we get

$x = ( - 2 \sqrt{6 } + \sqrt{2} ) \div 4$