Question

root 4.5 on no. line

Answer 1

ANSWER :-

• Draw a number line as shown in the attachment and mark 2 points ("A" & "B") and the distance between them should be 4.5.

• Extend the line from B one unit more and mark a point " C".

• The distance between A to C is 5.5 and we need more than half and we need to bisect A & C. To bisect A and C we will take C as centre and create an arc as shown in the diagram.

• In the same way now we take A as centre and cut the previously made arc. This point would be perpendicular to the line AC.

• Now, same process applying on the below of the diagram. Then we get two different points. and now we joint them with dotted line to get a perfect bisector pf line AC. The point when the dotted line intersects the line AC would be the point "O'.

• Now, with the help of compass and radius = OC we will construct an arc with O as a centre which cuts to the line on two points (A & C).

• And now with the help of protractor an B be the centre. We draw a point perpendicular to AC. We joint that point with point B to get perpendicular line. The point where the line intersects with arc which previously creates arc would be point " D ".

• Now, the length of BD would be equal to √4.5

• Take compass which radius = BD that be √4.5. With B as a centre create an arc which cuts to the line AC at certain arc. And name that point E.

• Here, the distance between B to E is √4.5 .