Question

root 5 +2root 3/root 7 +4root 3 =a-b root 3

Answer 1

plz mark it as brainliest...

Answer 2

$[tex]\frac{\sqrt{5} + 2\sqrt{3} }{ \sqrt{7 + 4 \sqrt{3} } } = a - b \sqrt{3} \\ \\ on \: rationlising \: the \: denominator \\ \\ we \: get \\ \\ = \frac{\sqrt{5} + 2\sqrt{3} }{ \sqrt{7 + 4 \sqrt{3} } } \times \frac{ \sqrt{7} - 4 \sqrt{3} }{ \sqrt{7} - 4 \sqrt{3} } \\ \\ = \frac{ (\sqrt{5} + 2 \sqrt{3} )( \sqrt{7} - 4 \sqrt{3}) }{ - 41} \\ \\ = \frac{\sqrt{35} - 4 \sqrt{15} + 2 \sqrt{21} - 24}{ - 41} \\ \\ = \frac{ - 24}{ - 41} + \frac{ \sqrt{35} - 4 \sqrt{15} + 2 \sqrt{21} }{ - 41} \\ \\ here \: a = \frac{24}{41} and \: - b \sqrt{3} = \frac{ \sqrt{35} - 4 \sqrt{15} + 2 \sqrt{21} }{ - 41}$ \\ [/tex]
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