Math, asked by malik45, 1 year ago

root 5 + root 3 / root 5 - root 3

Answers

Answered by DaIncredible
3
Hey friend,
Here is the answer you were looking for:
 \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  -  \sqrt{3} }  \\

On rationalizing the denominator we get,

 =  \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  -  \sqrt{3} }  \times  \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5}  +  \sqrt{3} }  \\

Using the identities :

 {(x + y)}^{?}  =  {x}^{2}  +  {y}^{2}  + 2xy \\ (x + y)(x - y) =  {x}^{2}  -  {y}^{2}

 =  \frac{ {( \sqrt{5}) }^{2}  +  {( \sqrt{3} )}^{2}  + 2( \sqrt{5} )( \sqrt{3}) }{ {( \sqrt{5} )}^{2} -  {( \sqrt{3} )}^{2}  }  \\  \\  =  \frac{5 + 3 + 2 \sqrt{15} }{5 - 3}  \\  \\  =   \frac{8 + 2 \sqrt{15} }{2}  \\  \\  = 4 +  \sqrt{15}

Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
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Answered by Anonymous
1
Hope it will help you
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