Question

Root 5 x^2 + 4x - root 5 factorise

Answer 1

$\sqrt{5} {x}^{2} + 4x - \sqrt{5} = 0$
first multiply first and last term

we get,

$- 5 {x}^{2}$
Now, find numbers such that the product is -5x^2 & sum is the middle term of the given quadratic equation .

THE NUMBERS ARE
5x & -x

Now.
dealing with the quadratic equation

The term 4x can also be written as
5x-x

so,

$\sqrt{5} {x}^{2} +5x - x - \sqrt{5} = 0$


$\sqrt{5} x(x + \sqrt{5}) - 1(x + \sqrt{5}) \\ =0$

$(x + \sqrt{5})( \sqrt{5} x- 1) = 0$

we get,

x+√5=0 or √5x-1=0

therefore ,


$x = - \sqrt{5 } \: or \: x = \frac{1}{ \sqrt{5} }$

$hope \: this \: helps$

Answer 2

Answer:

I hope that the above photo help you to understand.

Step-by-step explanation:

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