Question

Root 5x ^2-3root 6x -root 20 =0

Answer 1

d=b^2-4ac
=( 3√6)^2-4*5*√20
=54-20√20

Answer 2

Given:

given quadratic equation is 5x²-(3√6)x-√20

To Find:

find the roots of the equation.

Solution:

For the given equation we will apply the Sridharacharya formula.

a=5

b=-3√6

c=-√20=2√5

x={-b±√(b²-4ac)}/2a

 ={3√6±√(54-4×5×2√5)}/10

 ={3√6±√(54-40√5)}/10

x₁=$\frac{3\sqrt{6} +\sqrt{54-40\sqrt{5} } }{10}$

x₂=$\frac{3\sqrt{6} -\sqrt{54-40\sqrt{5} } }{10}$