Question

root 6 minus root 3 ​

Answer 1

Given: $\sqrt{6}-\sqrt{3}$

To find:

• To check whether irrational
• Conjugate

Solution:

• The given irrational number is $\sqrt{6}-\sqrt{3}$

• Now, $\sqrt{6}-\sqrt{3}$
• $=\sqrt{3}.\sqrt{2}-\sqrt{3}$, clearly an irrational number since both $\sqrt{2}$ and $\sqrt{3}$ are irrational.

• The conjugate of this irrational number is $\sqrt{6}+\sqrt{3}$ because when we find their product, they give a rational value.

Answer:

• Yes, irrational.
• $\sqrt{6}+\sqrt{3}$

Answer 2

Step-by-step explanation:

√6-√3=√3

Hope this helps

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