Question

root 6÷ root 2 +root 3 + 3root2 ÷ root6 +root3 - 4root2 ÷root6+root2 ​

Answer 1

$\frac{ \sqrt{6} }{ \sqrt{2} } + \frac{ \sqrt{3} + 3 \sqrt{2} }{ \sqrt{6} + \sqrt{3} } - \frac{4 \sqrt{2} }{ \sqrt{6} + \sqrt{2} }$