Question

Root 6 × root 6 × root 6 .......

Answer 1

Answer:

if there are even no of

root 6 then the answer would be an while no. of there are odd no then the answer would come in root

Answer 2

Answer:

Step-by-step explanation:

Given : x = √6 + √6 + √6 +... ---(i)

Then,

x = √6 + x --- From Eqn. (i)

On squaring both sides,

⇒ x² = 6 + x

⇒ x² - x - 6 = 0

⇒ x² - 3x + 2x - 6 = 0

⇒ x(x-3) + 2(x-3) = 0

⇒ x = 3 Or x = -2

But x is a natural number.

∴ x = 3