Question

root 6/root3-root2 by rationalising denominator​

Answer 1

Step-by-step explanation:

Refer to the picture for the steps

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Answer 2

Answer:

$\frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} }$

Can be multiplied by

$\frac{ \sqrt{ 3} + \sqrt{2} }{ \sqrt{ 3} + \sqrt{2} }$

So

$\frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{ 3 } + \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$\frac{ \sqrt{6} ( \sqrt{3 } + \sqrt{2} ) }{ { \sqrt{3} }^{2} - { \sqrt{2} }^{2} }$

$\frac{ \sqrt{6}( \sqrt{3} + \sqrt{2} ) }{3 - 2}$

$\frac{ \sqrt{6}( \sqrt{3} + \sqrt{2} ) }{1}$

Step-by-step explanation:

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