Math, asked by sadiyafathma827, 3 months ago

Root √7+√6upon root √7-√6

Answers

Answered by RealSweetie
0

 \frac{ \sqrt{7}  +  \sqrt{6} }{ \sqrt{7}  -  \sqrt{6} }  \\  =  \frac{( \sqrt{7}  +  \sqrt{6})( \sqrt{7} +  \sqrt{6} )  }{( \sqrt{7}  -  \sqrt{6})(  \sqrt{7}   +  \sqrt{6} ) }  \\  =  \frac{( \sqrt{7} +  \sqrt{6}) {}^{2}   }{( \sqrt{7}) {}^{2} - ( \sqrt{6}) {}^{2}    }  \\  =  \frac{( \sqrt{7} ) {}^{2} + 2 \sqrt{42} +  (\sqrt{6} ) {}^{2}   }{7 - 3}  \\  =  \frac{7 + 3 + 2 \sqrt{42} }{4}  \\  =  \frac{10 + 2 \sqrt{42} }{4}

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