root 7, minus root 7 are zeros of a quadratic polynomial then find the quadratic polynomial
Answers
Answered by
1
Step-by-step explanation:
α = 2√7 , β = -2√7
sum of zeros (α+β)= 2√7 + (-2√7)
= 2√7 - 2√7
= 0
product of zeros (αβ) = (2√7)(-2√7)
= -4×7
= -28
quadratic polynomial = [x²+(sum of zeros)x+product of zeros]
= [x²+ 0x + (-28)]
= x² + 0x - 28
or x² - 28
Answered by
1
Answer:
roots are : √7 and -√7 their sum = √7 + ( -√7) = 0
and product = √7 × ( - √7) = - 7
so,
required quadratic equations =
x² - ( sum)x + product = 0
or ,
x² - 0x + ( -7) = 0
or , x² -7 = 0 .
this is the required quadratic equation.
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