Question

root 7, minus root 7 are zeros of a quadratic polynomial then find the quadratic polynomial
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Answer 1

Step-by-step explanation:

α = 2√7 , β = -2√7

sum of zeros (α+β)= 2√7 + (-2√7)

                              = 2√7 - 2√7

                              = 0

product of zeros (αβ) = (2√7)(-2√7)

                                   = -4×7

                                   = -28

quadratic polynomial = [x²+(sum of zeros)x+product of zeros]

                                   = [x²+ 0x + (-28)]

                                   = x² + 0x - 28

                                   or x² - 28

Answer 2

Answer:

roots are : √7 and -√7 their sum = √7 + ( -√7) = 0

and product = √7 × ( - √7) = - 7

so,

required quadratic equations =

x² - ( sum)x + product = 0

or ,

x² - 0x + ( -7) = 0

or , x² -7 = 0 .

this is the required quadratic equation.

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