Question

root 7x+root 11y=0,root 3x-root 5y=0

Answer 1

By substitution,
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Answer 2

Answer:

Step-by-step explanation:

$\sqrt{7}x +\sqrt{11} y=0.....(i)$

$\sqrt{3}x -\sqrt{5} y=0......(ii)$

Linear equations

By using elimination method.

On multiplying equation (i) by  $\sqrt{3}$ and equation (ii) by $\sqrt{7}$.

we get,

$\sqrt{21}x +\sqrt{33} y=0 ......(iii)$

$\sqrt{21}x -\sqrt{33} y=0........(iv)$

On subtracting equation (iv) from equation (iii). we get,

$21x+33y=0$  

$\frac{\sqrt{21}x-\sqrt{35}y=0}{\sqrt{33}x+\sqrt{35}y=0}$      

⇒y=0

On substituting y=0 in equation (i).

we get,

$\sqrt{7}x +\sqrt{11} y=0$

⇒ $\sqrt{7} x=0$

⇒$x=0$

∴ $x=0,y=0$

Hence proved.$\sqrt{7}x +\sqrt{11} y=0$,$\sqrt{3}x -\sqrt{5} y=0$

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