root find karo two
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Answer:
roots for the given equation are (b+4) and (b-5)
Step-by-step explanation:
Answer for the given problem in two methods
x²-(2b-1)x+(b²-b-20)=0
=>x²-(2b-1)x+(b²-5b+4b-20)=0
=>x²-(2b-1)x+(b-5)(b+4)=0
=>x²-[(b-5)x+(b+4)x]+(b-5)(b+4)=0
=>x(x-(b-5))-(b+4)(x-(b-5))=0
=>(x-(b-5))(x-(b+4))=0
=>x-(b-5)=0 or x-(b+4)=0
=>x=(b-5) and x=(b+4)
The roots are (b-5) and (b+4)
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refer the attachment bro
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