Math, asked by siddharthpawar00242, 8 months ago

root fof quadratic equation y2 -16y+63=0​

Answers

Answered by Anonymous
1

Step-by-step explanation:

y² - 16y + 63 = 0

=> y² - 9y - 7y + 63 = 0

=> y( y-9 ) -7( y-9 ) = 0

=> ( y-9 ) ( y-7 ) = 0

=> y = 9, 7

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