Question

root of 1+ sin A * root of 1 - sin A equal to​

Answer 1

Answer:

Step-by-step explanation:

i) (a-b)(a+b)= a^{2}- b^{2} , the difference of squares formula.

ii) sin^{2} x+cos^{2}x=1, for any angle x.

Then,

from i)

\sqrt{(1-sin(theta))(1+sin(theta))}= \sqrt{1- sin^{2}(theta) }

then, from ii), we have

\sqrt{1- sin^{2}(theta) }= \sqrt{cos^{2}(theta) }=cos(theta)

Answer: cos(theta)

Answer 2

root of 1+ sin A * root of 1 - sin A equal to = cos (theta)