Math, asked by jayaAnoop06, 11 months ago

(Root of 3+root of 5)(root of 12-root of 5root of 15

Answers

Answered by mysticd
1

Answer:

6-15\sqrt{5}+\sqrt{60}-25\sqrt{3}

Step-by-step explanation:

(\sqrt{3}+\sqrt{5})(\sqrt{12}-5\sqrt{15})

=\sqrt{3}(\sqrt{12}-5\sqrt{15})+\sqrt{5}(\sqrt{12}-5\sqrt{15})

=\sqrt{3}\times 2\sqrt{3}-\sqrt{3}\times 5\sqrt{5\times 3}\\+\sqrt{5}\times \sqrt{12}-\sqrt{5}\times5\sqrt{15}

=6-15\sqrt{5}+\sqrt{60}-25\sqrt{3}

•••♪

Answered by vilnius
0

6  + 2\sqrt{15} - 15 \sqrt{5} -  25\sqrt{3}

Step-by-step explanation:

Given,

(\sqrt{3} + \sqrt{5})  (\sqrt{12} - 5\sqrt{15})

\\(\sqrt{3} + \sqrt{5})  (2\sqrt{3} - 5\sqrt{15})

Multiplying:

(\sqrt{3} × 2\sqrt{3}) + (\sqrt{5} × 2\sqrt{3}) - (\sqrt{3} × 5\sqrt{15}) - (\sqrt{5} × 5\sqrt{15})

Removing the square root from the perfect squares:

(3 × 2) + ( 2\sqrt{15}) - (\sqrt{3} × 5\sqrt{3 * 5}) - (\sqrt{5} × 5\sqrt{3 * 5})

(6)  + ( 2\sqrt{15}) - (3 × 5 \sqrt{5}) - (5 × 5\sqrt{3})

(6)  + ( 2\sqrt{15}) - (15 \sqrt{5}) - (25\sqrt{3})

6  + 2\sqrt{15} - 15 \sqrt{5} -  25\sqrt{3}

Learn more:

Factorise the following

brainly.in/question/6734488

brainly.in/question/12938195

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