root of 5 x^2+x+root of 5 =0
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Answer:
By splitting the middle term we get
x^2- under root 5x - 1x + under root 5 =0
taking common
x (x-root 5 ) - 1 (x-root 5 ) = 0
(x-1)(x-root 5 )=0
so
x-1=0; x=1
also
x-root 5=1
x= root 5
hence we get
x = 1 ; roit
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