Question

root of quadratic equation.
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Answer 1

here quandratic formula is used to get tge roots

Answer 2

${x}^{2} - 2ax + {a}^{2} - {b}^{2} \\ {(x - a)}^{2} - {b}^{2} \\ (x - a + b)(x - a - b) = 0 \\ x - a + b = 0 \: \: \: \: or \: \: \: x - a - b = 0 \\ x = a - b \: \: \: or \: \: x = a + b$