Question

root of quadratic equation y2 -16y+63=0​

Answer 1

y2 -16y+63=0

or, y2-9y-7y+63 = 0

or, y(y-9)-7(y-9) = 0

or, (y-9)(y-7) = 0

or, y =9, 7

So, Roots are 9 and 7.

Answer 2

Answer:

x = 7,9

Step-by-step explanation:

y² - 16y + 63 = 0

=> y² - 9y - 7y + 63 = 0

=> y(y - 9) - 7(y - 9) = 0

=> (y-7)(y-9) = 0

therefore, x = 7,9