Question

root of
$\sqrt[2x]{x - 4}$

Answer 1

Q:- 2x√( x - 4 )

=( x - 4 )^(1/2 x)

=( x - 4 )^(x/2 )

let we solve it for minimum value of ' x '

min( x - 4 )^x/2 = 0

x - 4 = (0)^2x

x - 4 = 0

x = 4
_______________________________
Your Answer : x = 4
_______________________________