root of
![\sqrt[2x]{x - 4}](https://tex.z-dn.net/?f=+%5Csqrt%5B2x%5D%7Bx+-+4%7D+ "\sqrt[2x]{x - 4}")
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Q:- 2x√( x - 4 )
=( x - 4 )^(1/2 x)
=( x - 4 )^(x/2 )
let we solve it for minimum value of ' x '
min( x - 4 )^x/2 = 0
x - 4 = (0)^2x
x - 4 = 0
x = 4
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Your Answer : x = 4
_______________________________
=( x - 4 )^(1/2 x)
=( x - 4 )^(x/2 )
let we solve it for minimum value of ' x '
min( x - 4 )^x/2 = 0
x - 4 = (0)^2x
x - 4 = 0
x = 4
_______________________________
Your Answer : x = 4
_______________________________
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